Python, integer processing as string.

Asked Jul 23 '15 at 23:42

Active Jul 23 '15 at 23:43

Viewed 21 times

Beginner here learning python. I'm having an issue processing the follwing code. I'm trying to compare numbers but I am getting an "unorderable type error". I don't understand why, as both numbers being compared are integers.

winning_number = 5

guess = input("Can you guess the lucky number.\nHint it's between 1 and 10!\n")

def compare(guess):
    if guess > winning_number:
        print ("Wrong, you're guess is too high")
    elif guess < winning_number:
        print ("Wrong, you're guess is too low")
    else:
        pass

compare(guess)

asked Jul 23 '15 at 23:42

MJ49

You may try using `guess = int(input("Can you guess the lucky number.\nHint it's between 1 and 10!\n"))`. From the code it seems that you are using Python3.x, and the `input()` returns a `str` in that case – ZdaR Jul 23 '15 at 23:44
Your else is also redundant – Padraic Cunningham Jul 23 '15 at 23:49
Ah! I see. Yes, I am using Pyhton3, and your tip worked! Thanks! – MJ49 Jul 24 '15 at 00:06

Python, integer processing as string.

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