I am new to c programming.I need a (10^5)*(10^5)
matrix within which I define a circular boundary.The matrix entries inside boundary will be 1 and outside 0.For checking I have started with (1000*1000)
and it prints the whole matrix if I don't use the free(ar)
statement.And when I am using (11*11)
matrix and changing the circular boundary accordingly and checking the free(ar)'s
action by printing first row it shows previous entries.I am using windows 64 bit machine,and code::blocks 13.12 IDE.This is my code for (11*11) matrix:
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
#include<conio.h>
#include<time.h>
#define NULL ((void *)0)
main()
{
int i,j,n,k,*ar;
float p;
printf("Enter n::::");
scanf("%d",&n);
ar=(int*)calloc((n*n),sizeof(int));
if(ar==NULL)
{
printf("Memory allocation error");
exit(1);
}
printf("\nThe matrix is::\n");
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
p=((i-5)*(i-5)+(j-5)*(j-5));
if(p<16)
{
ar[i*n+j]=0;
printf("%d",ar[i*n+j]);
}
else
{
ar[i*n+j]=1;
printf("%d",ar[i*n+j]);
}
}
printf("\n");
}
printf("\nPRINTING COMPLETE\n");
free(ar-(n*n));
printf("\nThe first row of the matrix is\n\n");
for(k=0;k<11;k++)
{
printf("%d\t",*(ar+k));
}
}
The output is:
Enter n::::11
The matrix is::
11111111111
11111111111
11100000111
11000000011
11000000011
11000000011
11000000011
11000000011
11100000111
11111111111
11111111111
PRINTING COMPLETE
The first row of the matrix is
1 1 1 1 1 1 1 1
1 1 1