How Do I Convert Strings To Int?

Question

I am having three textboxes one inputting hours, one numbers and one power rate and a button but am having a formatException whenever i try to input values in the textboxes. How can i fore go this please? Whenever i compile it runs well but i am unable to input the values. Help please. Thanks!

int num1 = int.Parse(TextBox1.Text);

double num2 = double.Parse(TextBox2.Text;);

int num3 = int.Parse(TextBox3.Text;);
soln1 = num1 * num2 * num3;
MessageBox.Show(soln1.ToString());

On which line you get this exception? What is your textbox values? What is your `CurrentCulture`? You have an extra `;` in your code by the way. — Soner Gönül, Jul 28 '15 at 08:09
do you really have double.Parse(TextBox2.Text;); instead if double.Parse(TextBox2.Text); — demonplus, Jul 28 '15 at 08:09

score 2 · Answer 1 · answered Jul 28 '15 at 08:12

2

try to change parse to convert like this

int num1 = Convert.ToInt32(TextBox1.Text);  
double num2 = Convert.ToDecimal(TextBox2.Text;);
int num3 = Convert.ToInt32(TextBox3.Text;);
soln1 = num1 * num2 * num3;
MessageBox.Show(soln1.ToString());

answered Jul 28 '15 at 08:12

kulotskie

331
1
16

score 0 · Answer 2 · answered Jul 28 '15 at 08:11

0

You are trying to multiply a double and an integer. Try casting your integer to a double, and declare the variable you are going to store the result in as a double too.

If it really needs to be an integer then convert it after the calculation

answered Jul 28 '15 at 08:11

DrLazer

2,805
3
41
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the problem is with converting string to numbers not type of numbers – M.kazem Akhgary Jul 28 '15 at 08:15
on the second to last line, int*double will never work. there is more than one problem – DrLazer Jul 28 '15 at 08:17
no.result of int*double is double. you can try it. there is no issue there except if the type of `soln1` is int. – M.kazem Akhgary Jul 28 '15 at 08:20
ah yeah .. we are talking about the same issue. int x = * = BOOM – DrLazer Jul 28 '15 at 11:49

score 0 · Accepted Answer · answered Jul 28 '15 at 08:11

0

Try

int num1 = int.Parse(TextBox1.Text);

double num2 = double.Parse(TextBox2.Text.Replace(".", ",")); // <---- 

int num3 = int.Parse(TextBox3.Text;);
soln1 = (int)(num1 * num2 * num3); // <----
MessageBox.Show(soln1.ToString());

answered Jul 28 '15 at 08:11

Nikita Ilin

94
5

score 0 · Answer 4 · answered Jul 28 '15 at 08:11

0

Instead of using parse use TryParse, like that:

if (int.TryParse(TextBox1.Text,out num1) &&
double.TryParse(TextBox2.Text,out num2) &&
int.TryParse(TextBox3.Text,out num3))
{
   soln1 = num1 * num2 * num3;
}

answered Jul 28 '15 at 08:11

israel altar

1,768
1
16
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1

@ShaddyWizKay dont forget to mark this as answer if it solved your problem – M.kazem Akhgary Jul 28 '15 at 15:44

score 0 · Answer 5 · edited Jul 28 '15 at 09:10

0

Try using:

int num1 = integer.parseInt(TextBox1.Text);
double num2 = double.Parse(TextBox2.Text);

int num3 = Integer.ParseInt(TextBox3.Text);
soln1 = num1 * num2 * num3;
MessageBox.Show(soln1.ToString);

edited Jul 28 '15 at 09:10

GrandMasterFlush

6,269
19
81
104

answered Jul 28 '15 at 08:18

mikyle

1

How Do I Convert Strings To Int?

5 Answers5