How to group(using set()) for every n elements in an array: python

Asked Jul 29 '15 at 19:37

Active Jul 29 '15 at 19:37

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I apologize if this question is already asked but i am not able to find the answer. I have a list of elements. I wanted to group elements for every 4 elements in the array. Example:

my_list = ["A","B","C","D","E","F","G","H",....]

result = [{"A","B","C","D"},{"E","F","G","H"},....]

asked Jul 29 '15 at 19:37

Gautam

1

Split into evenly sized chunks (see the duplicate) and make each chunk a set. Using the function from the top answer that'd be `[set(c) for c in chunks(my_list, 4)]`. – Martijn Pieters Jul 29 '15 at 19:38
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`it = iter(my_list)print([set(zip(it,it,it,it))])`, resuming all values are unique – Padraic Cunningham Jul 29 '15 at 19:39
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thank you. Your answer is helpful – Gautam Jul 29 '15 at 19:50

How to group(using set()) for every n elements in an array: python

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