PHP unexpected T_Variable with if( ... or ...)

Asked Jul 30 '15 at 00:43

Active Jul 30 '15 at 00:43

Viewed 22 times

I tried the following first, which seems the most intuitive thing to do:

if ($obj->request_method != 'post' || $uid < 1)
    die();

But had the error:

Parse error: syntax error, unexpected '$uid' (T_VARIABLE)

So I tried this, which fixed that error.

if (($obj->request_method != 'post') || ($uid < 1))
    die();

But when I go to another page, where this if is used, I get the following error:

Fatal error: Call to undefined function  () in

It is not related to the rest of the code. I'm wondering why simple ifs are failing, is it a sign that I need more sleep?

asked Jul 30 '15 at 00:43

This looks very much like you have an unmatched single-quote somewhere in a preceding line. – Jul 30 '15 at 00:45
Cannot reproduce your error. Please show us an example to reproduce your error – Rizier123 Jul 30 '15 at 00:46
2

5¢ on Unicode whitespace. – mario Jul 30 '15 at 00:48
Bingo! I had to remove a specific space and change it into a new space. Then it worked. Wow.. haha Thanks for the help! :D – Kevin Van Ryckegem Jul 30 '15 at 01:01

0 Answers0