Regular Expression - Regex expression between 0 and 13.6

Question

I've been asked on how to do a regex expression bewtween 0 and 13.6, but i really dont know.. anyone could help?

Thanks

I've looked some examples, but could make it less than a specific double — sir_ask, Jul 30 '15 at 20:24
[Please post the code you've attempted](http://whathaveyoutried.com) — zzzzBov, Jul 30 '15 at 20:25
Regular expressions are not usually the best tool for checking numeric ranges. Why do you need to do it this way? — Barmar, Jul 30 '15 at 20:27

zolo · Accepted Answer · 2015-07-31T05:56:27.607

0

^([0-9](?:\.[0-9]+)?|1[0-2](?:\.[0-9]+)?|13(?:\.[0-5][0-9]+)?|13(?:\.60*)?)$

edited Jul 31 '15 at 05:56

answered Jul 30 '15 at 20:31

zolo

1

i've not tested.. but it's similar to what i got working. Thanks – sir_ask Jul 30 '15 at 20:40
Didn't see that you got solution for this, didn't know that you have a working one already. – zolo Jul 30 '15 at 20:44
This has issues. It won't match `13`, `13.0`, or `13.12`. You're allowing `0-12` to have optional decimals and multiple decimal places. But for `13`, it must be: `13.1`, `13.2`, `13.3`, `13.4`, `13.5`, or `13.6` only. – Bond Jul 31 '15 at 04:01
corrected the regexp. but I dont understand clearly, how many digits can have after the decimal point? – zolo Jul 31 '15 at 05:57

maraaaaaaaa · Answer 2 · 2015-07-30T21:02:40.920

0

(?<![\.\d])\d\b(?:\.\d+)?|(?<=1)[0-2]\b(?:\.\d+)?|(?<=13)\.?[0-2]?|(?<=13.5)(?:\.\d+)?|13\.6

this will find every instance that exists in a string, doesnt necessarily have to start and end as the number

edited Jul 30 '15 at 21:02

answered Jul 30 '15 at 20:57

maraaaaaaaa

2 Answers2