How to get array's col and row for specific values in python numpy?

Question

I have an array like this :

a = np.array([[23,31,42],[16,22,56],[33,11,51]])
b = a.min()
print a
print b

So the result will be like this :

 [[23 31 42]
  [16 22 56]
  [33 11 51]]
 11

How do i get row and column of a specific value inside that array? for example :

If i want value = b where b is 11, then i'll get 2 and 1 remind that a[2][1] = 11

In my case, i need to get the row and column of the lowest value in my array.

possible duplicate of [Is there a Numpy function to return the first index of something in an array?](http://stackoverflow.com/questions/432112/is-there-a-numpy-function-to-return-the-first-index-of-something-in-an-array) — innoSPG, Jul 30 '15 at 23:12

Saullo G. P. Castro · Accepted Answer · 2015-07-30T23:32:50.793

1

What you want is:

np.where(a == a.min())

if a is an array of floats you should use instead:

np.where(np.allclose(a, a.min()))

edited Jul 30 '15 at 23:32

answered Jul 30 '15 at 23:12

1 Answers1