How to convert variable value into jQuery object?

Question

For some reason I need to convert jquery variable value into object.

$("input[type=text]").on("keyup", function () {
    var target = this.id; //outputs 'subject'
    //how to convert here?
    var targetItem = $("#subject");//originally like this.
    //I tried something like below
    //var targetItem = $("#+target+");
    alert(targetItem);
});

All I'm trying to do is , changing the word in this: $("#subject") with whatever value of variable 'target'.

http://stackoverflow.com/questions/12134605/concatenate-in-jquery-selector/12134652#12134652 — sabithpocker, Jul 31 '15 at 10:52
just one doubt. Why do you need this code? because object which you will get is same one you get by simply using `this` — Amit.rk3, Jul 31 '15 at 10:53
Provide minimalistic sample to replicate your issue because your posted code doesn't make sense or maybe your example sample isn't relevant to your use case issue — A. Wolff, Jul 31 '15 at 10:55

Sougata Bose · Answer 1 · 2015-07-31T10:56:33.403

2

Use this -

var targetItem = $(this); // Will always hold the current element object

And for the code you are using it should be -

var targetItem = $("#" + target);

target is a variable. "#+target+" will be treated as #+target+ not #subject (in your case)

edited Jul 31 '15 at 10:56

answered Jul 31 '15 at 10:54

Sougata Bose

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You can also please correct the way he is trying to concatenate `string`s – sabithpocker Jul 31 '15 at 10:55
@sabithpocker :) Thanks. – Sougata Bose Jul 31 '15 at 10:58
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@A.Wolff Thank you for doing my part :P – sabithpocker Jul 31 '15 at 10:59
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@sabithpocker You Are Welcome. ;) – Sougata Bose Jul 31 '15 at 11:00

score 1 · Accepted Answer · answered Jul 31 '15 at 10:50

1

Simply like

var target = this.id;
var targetItem = $("#"+target);

answered Jul 31 '15 at 10:50

Sudharsan S

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But because IDs must be unique on document context, it doesn't make sense – A. Wolff Jul 31 '15 at 10:54
@soosmca No need id value ,You can use this directly **$(this)** – Balachandran Jul 31 '15 at 10:54
@Balachandran - I am just notices what mistake the OP had done – Sudharsan S Jul 31 '15 at 11:01
That is good but i gave suggestion you can wrap *this* with $ directly – Balachandran Jul 31 '15 at 11:36

How to convert variable value into jQuery object?

2 Answers2