Perl does something very similar to this, and the results are sometimes surprising. You'll find warnings about this in many Perl texts; for example, this one comes from the standard distributed Perl documentation (man perlfunc
):
Any function in the list below may be used either with or without parentheses around its arguments. (The syntax descriptions omit the parentheses.) If you use parentheses, the simple but occasionally surprising rule is this: It looks like a function, therefore it is a function, and precedence doesn't matter. Otherwise it's a list operator or unary operator, and precedence does matter. Whitespace between the function and left parenthesis doesn't count, so sometimes you need to be careful:
print 1+2+4; # Prints 7.
print(1+2) + 4; # Prints 3.
print (1+2)+4; # Also prints 3!
print +(1+2)+4; # Prints 7.
print ((1+2)+4); # Prints 7.
An even more surprising case, which often bites newcomers:
print
(a % 7 == 0 || a % 7 == 1) ? "good" : "bad";
will print 0 or 1.
In short, it depends on your theory of parsing. Many people believe that parsing should be precise and predictable, even when that results in surprising parses (as in the Python example in the linked question, or even more famously, C++'s most vexing parse). Others lean towards Perl's "Do What I Mean" philosophy, even though the result -- as above -- is sometimes rather different from what the programmer actually meant.
C, C++ and Python all tend towards the "precise and predictable" philosophy, and they are unlikely to change now.