Reading text file in C++

Asked Jul 31 '15 at 12:02

Active Jul 31 '15 at 12:19

Viewed 54 times

I want to read a text file of the form.

15 23 63 52 58
11 254 55 36 22 547 55 2 
22 58 66 3 11 4 7 5 2 8 
48 49 23 88 62 33

How can I implement it in C++? The following code has been implemented by me.

while(!fin.eof()) {
    getline(fin, str);
    cout << str << "\n\n";
    i++;    
}

Here the numbers are in the form of a string. Since the code is a part of reading adjacency list of graph, I want the array of these numbers. For example, I want to create a C++ vector array

vector<int> abc[4];

where I will store all the corresponding numbers in the line. Please suggest a solution other than reading the numbers in form of string and splitting it. It should be concise than earlier one.

edited Jul 31 '15 at 12:19

asked Jul 31 '15 at 12:02

LearningToCode

_Better_ is a relative term. What do you mean exactly? How would a solution be better than reading each line and splitting? – rodrigo Jul 31 '15 at 12:06
1

You don't tell us *how* you want to represent this data in your program. Is it just a `vector`, or is it a `vector>`? – crashmstr Jul 31 '15 at 12:07
1

Do you want all numbers in a single collection without any regards for the line separators? Or do you want the number on each line in a separate collection? – Some programmer dude Jul 31 '15 at 12:09
1

[Don't use `!fin.eof()`](http://stackoverflow.com/questions/5431941/why-is-while-feof-file-always-wrong) – NathanOliver Jul 31 '15 at 12:24
@KaranMehta Did you read the link? – NathanOliver Jul 31 '15 at 14:28
@NathanOliver now I realize why the count in the loop was greater by 1 than the actual one.. – LearningToCode Jul 31 '15 at 16:19

Reading text file in C++

0 Answers0