How to get the actual file object from Camel FTP route exchange

Question

In my Camel router:

from(<SourceURI>)
.process(new Processor() {
    @Override
    public void process(Exchange exchange) throws Exception {
        // I want to extract the file object from the exchange
    }
.to(<targetURI>).

How can I achieve this?

I tried e.g. exchange.getIn().getHeader(Exchange.FILE_NAME, String.class) which gives me the file name. I am searching for something Exchange.FILE which gives me the actual file object. My Ultimate goal is to extract the file in the processor as the routed exchange is an archive file.

score 12 · Answer 1 · answered Aug 03 '15 at 07:36

12

Get the file from the body. Camel uses a 'org.apache.camel.component.file.GenericFile' to store as the file body. But you can use Camel's type converters to get the file in a type you want.

For example you can get the content in different types, such as:

String text = exchange.getIn().getBody(String.class);
byte[] bytes = exchange.getIn().getBody(byte[].class);
InputStream is = exchange.getIn().getBody(InputStream.class);

answered Aug 03 '15 at 07:36

Claus Ibsen

56,060
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If you want the filename use `String filename = exchange.getIn().getBody(GenericFile.class).getFileName();` – asmaier Oct 02 '15 at 15:21
Maybe your message body is null? – asmaier Jul 17 '18 at 07:24

score 3 · Answer 2 · answered Nov 15 '18 at 16:40

3

For those who have a from("file:...") the following works:

File in = exchange.getIn().getBody(File.class);

answered Nov 15 '18 at 16:40

Gerold Broser

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How to get the actual file object from Camel FTP route exchange

2 Answers2