Python lambda function with indexing

Asked Aug 04 '15 at 14:30

Active Aug 05 '15 at 09:06

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I know similar questions have been asked, but I have no idea how to apply it to my problem. I am trying to create a tuple with lambda functions which call an array index.

cons=()
for i in range(5):
    cons = cons + (lambda x: x[i],)

All the functions in the tuple use the latest value of i, instead of the initial value. How do I fix this in this example?

Just for completeness sake, I have solved my problem with the below solution:

def indexi(x,j):
  return(x[j])

def indexii():
    for i in range(5):
        yield(partial(indexi, j=i))

cons=()
for func in indexii():
    cons += (func_,)

edited Aug 05 '15 at 09:06

asked Aug 04 '15 at 14:30

Chris

3

Possibly duplicate, see http://stackoverflow.com/questions/21053988/lambda-function-acessing-outside-variable – Dov Grobgeld Aug 04 '15 at 14:33
1

Not an answer to your question but you could use `operator.itemgetter` instead of the lambda function – Justin Fay Aug 04 '15 at 14:35

Python lambda function with indexing

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