As already said in the comments, you need to put it in the closure. Here's an example:
function timer() {
for (i = 100; i >= 0; i--) {
setTimeout(function(t) {
return function() {
var timer = t.toString() + "%";
$('#innerBar').css("width", timer);
};
}(i), ((100 - i) * 1000));
}
}
timer();
#innerBar {height: 50px; background: green; transition: width 0.2s linear}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="innerBar"></div>
EXPLANATION
So my question are: what is going throught function(t)? and why and how does }(i) work? Is it a multiplication of the fu?
Let's take the function body we're passing in to setTimeout:
function(t) {
return function() {
var timer = t.toString() + "%";
$('#innerBar').css("width", timer);
};
}(i)
Let's omit the inside part:
function(t) {
// do some stuff with t
}(i)
Looks familiar? It's like the function body is called right away and is called an IIFE, just like, say:
(function(a, b) {
return a + b;
})(2, 3) // returns 5
So back to the original function, it accepts one parameter, t
, and when we're calling the function we're passing in the iterator i
as an argument (so the value of i
becomes t
inside the function). As I said in the comment, this is necessary in order to "fetch" the current value of i
instead of getting the post-loop value.