Why does my python bash subprocess show a cant open file error?

Question

I have a python tile menu script where a subprocess executes a bash shell:

    # excute shell script
    subprocess.call([self.path + '/pimenu.sh'] + actions)

and in the shell I have:

   python ./to/file/name/"$*".py

but when the python script which is found and executed returns an error as it cant find the folder with the images in.:

  pygame.error: Couldn't open ./file/name/image.jpg

I am assuming it is looking in the folder the menu script is in, how can I give python or bash the correct path to the scripts resources?

it finds the .py file but not the folder thats the images are in. — pythonhunter, Aug 05 '15 at 12:57
why is one path `./to/file/name/` and the other `./file/name/`? I would try passing full paths and see how that goes — Padraic Cunningham, Aug 05 '15 at 13:23
Is this question not useful or legitimate? Why the down vote? — pythonhunter, Aug 06 '15 at 10:12

score 0 · Answer 1 · edited May 23 '17 at 10:26

0

You can use a path finding built in python's os package into the scripts ./to/file/name/"$*".py like this:

import os
print os.getcwd()

It is good enought described into the next SO answer: https://stackoverflow.com/a/3430395/2261861

edited May 23 '17 at 10:26

Community

answered Aug 05 '15 at 13:25

Max Vyaznikov

1 Answers1