Is return better than yield? From what ive read it can be. In this case I am having trouble getting iteration from the if statement. Basically what the program does is take two points, a begin and end. If the two points are at least ten miles apart, it takes a random sample. The final if statement shown works for the first 20 miles from the begin point, begMi. nCounter.length = 10 and is a class member. So the question is, how can I adapt the code to where a return statement would work instead of a yield? Or is a yield statement fine in this instance?
def yielderOut(self):
import math
import random as r
for col in self.fileData:
corridor = str(col['CORRIDOR_CODE'])
begMi = float(col['BEGIN_MI'])
endMi = float(col['END_MI'])
roughDiff = abs(begMi - endMi)
# if the plain distance between two points is greater than length = 10
if roughDiff > nCounter.length:
diff = ((int(math.ceil(roughDiff/10.0))*10)-10)
if diff > 0 and (diff % 2 == 0 or diff % 3 == 0 or diff % 5 == 0)\
and ((diff % roughDiff) >= diff):
if (nCounter.length+begMi) < endMi:
vars1 = round(r.uniform(begMi,\
(begMi+nCounter.length)),nCounter.rounder)
yield corridor,begMi,endMi,'Output 1',vars1
if ((2*nCounter.length)+begMi) < endMi:
vars2 = round(r.uniform((begMi+nCounter.length),\
(begMi+ (nCounter.length*2))),nCounter.rounder)
yield corridor,begMi,endMi,'Output 2',vars1,vars2
So roughdiff equals the difference between two points and is rounded down to the nearest ten. Ten is then subtracted so the sample is taken from a full ten mile section; and that becomes diff. So lets say a roughDiff of 24 is rounded to 20, 20 - 10, diff + begin point = sample is taken from between mi 60 and 70 instead of between 70 and 80.
The program works, but I think it would be better if I used return instead of yield. Not a programmer.