Python : How to search for values in a table outside an if function?

Question

I'm trying to create an application using python that lets the Admin of the app delete an user by matching his name in the list

Here is the code :

    class Personne:
        def __init__(self, prenom, nom):
            self.prenom = prenom
            self.nom = nom

        def __str__(self):
            return "{0} {1} {2}".format(self.prenom, self.nom)


    class SuperUser(Personne):
        def __init__(self, nom, prenom, droit, arg=0):
            Personne.__init__(self, prenom, nom)
            self.droit = droit
            self.arg = arg

        def __str__(self):
            return "{0} {1} is {2}".format(self.prenom, self.nom, self.droit)



    Utilisateur1 = SuperUser("Chris", "Cat", "Admin", "John")
    Utilisateur2 = SuperUser("John", "Doe", "Membre")
    Utilisateur3 = SuperUser("Karma", "Frost", "Membre")
    Utilisateur4 = SuperUser("Emma", "Stone", "Staff")

    list = [Utilisateur1, Utilisateur2, Utilisateur3, Utilisateur4]

    for utilisateur in list:
        print "From list:" + str(utilisateur)

        if utilisateur.droit == "Admin":
            print utilisateur.arg

            #utilisateur.nom takes my name which is Chris and should take the name of John Doe which is Utilisateur2
            if utilisateur.arg == utilisateur.nom: 
                print utilisateur.nom #the part for deleting an user would be creater later.

How can I make it so that in the last 2 lines, utilisateur.arg takes the name as Utilisateur2 from the list?

Sidenote: Having `arg` as either 0 or a string with the name of a user is a little strange API-wise IMHO. The conventional value for ”no value” is `None` in Python. — BlackJack, Aug 12 '15 at 16:35

score 2 · Accepted Answer · edited May 23 '17 at 11:53

2

If I understood your question correctly, you would like to find matches of utilisateur.arg in the list. Your condition is that the list's item.nom == utilisateur.arg.

This code should do the trick:

utilisateur2 = next((u for u in list if u.nom == utilisateur.arg), None)
if utilisateur2 == None:
   # not found

References:

edited May 23 '17 at 11:53

Community

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answered Aug 12 '15 at 14:41

ypnos

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The solution works fine thanks! I have a question with this method, how do you render the name only ? I tried `print utilisateur2.nom` but gives me an Attribute error. – Horai Nuri Aug 12 '15 at 15:48
@Sia That can't be because then the comparison in the generator expression already would have raised that `AttributeError`. – BlackJack Aug 12 '15 at 16:23

Python : How to search for values in a table outside an if function?

1 Answers1