0 cant be divided using try and catch java

Question

How do I make my program to not allow the user to divide by zero? If you divide by zero the program will handle the exception and display message “Please input another integer than zero" using try and catch

import java.util.*;

public class Calculation {
  public static void main(String args[] ){
    Scanner s = new Scanner(System.in);
    int num1 = 0, num2 = 0, answer;
    try {
      if (num1 == 0) {
        System.out.print("Enter first integer to be divided: ");
        num1 = s.nextInt();
        System.out.println("Please input another integer than zero");
      } else if (num2 == 0) {
        System.out.print("Enter second integer to be divided: ");
        num2 = s.nextInt();
        System.out.println("Please input another integer than zero");
      } else {
        answer = num1/num2;
        System.out.println("Answer is: " + answer );
      }
    } catch(Exception e) {
      System.out.println("Answer is: " + e.getMessage());
    }
  }
}

`if(num2 == 0){System.out.println("Please input another integer than zero"}` — brso05, Aug 12 '15 at 15:37
`try{int i = 3/0;}catch(ArithmeticException e){//handle here}` — brso05, Aug 12 '15 at 15:39

score 0 · Accepted Answer · edited May 23 '17 at 11:51

0

Simply throw-catch an Exception such as proposed ArithmeticException or create your own:

try {
    if(num2 == 0){
        throw new ArithmeticException();
    }
} catch (ArithmeticException e) {
    System.out.println("Please input another integer than zero");
}

edited May 23 '17 at 11:51

Community

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answered Aug 12 '15 at 15:45

Jordi Castilla

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0 cant be divided using try and catch java

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