How to remove all String text before equals ('=') sign Java

Question

I'd like to parse a string so I can build an XML document.

I have:

String value = "path=/Some/Xpath/Here";

I've parsed it this way:

private void parseXpath() {
    String s = "path=/Some/Xpath/Here";

    String[] tokens = s.split("/");
    for(String t: tokens){
        System.out.println(t);
    }
}

output:

path=
Some
Xpath
Here

How can I remove "path=" altogether? I want just the values from xpath?

Edit:

Thanks for the responses.

How can I make this method into one which returns String[],

Example:

private String[] parseXpath(String s) {

String[] tokens = s.replaceFirst(".*=", "").split("/");
   for(String t: tokens){
      System.out.println(t);
   }
   return tokens;
}

My output is:

[Ljava.lang.String;@413849df

How can I make it return me array of strings?

it already returns a array of string, but you cant just throw it into System.out.println(...); that would just print its object-id. you need to iterate the array to print its contents — ChrisKo, Aug 12 '15 at 18:34

Avinash Raj · Accepted Answer · 2015-08-12T18:14:47.333

6

Just do replace before splitting.

String[] tokens = s.replaceFirst(".*=", "").split("/");

This would give you an empty element at first because it would do splitting on the first forward slash after replacing.

or

String[] tokens = s.replaceFirst(".*=/", "").split("/");

But if you remove all the chars upto the = along with the first forward slash will give you the desired output.

edited Aug 12 '15 at 18:14

answered Aug 12 '15 at 18:11

Avinash Raj

172,303
28
230
274

replacing *= with "" will replace it with an empty line, how could it be no empty line – mosawi Aug 12 '15 at 18:13
`".*="` would match all the chars upto the equal sign. – Avinash Raj Aug 12 '15 at 18:16
I edited my question, how could I make it into a method returning a value – mosawi Aug 12 '15 at 18:30
Use `Arrays.toString()` method. – Avinash Raj Aug 12 '15 at 18:31
Can you elaborate, I'm new to this stuff – mosawi Aug 12 '15 at 18:32

score 3 · Answer 2 · answered Aug 12 '15 at 18:17

3

Although the question is tagged with regex here is a solution using substring

    String[] tokens = s.substring(s.indexOf("=") + 1).split("/");

or

    String[] tokens = s.substring(s.indexOf("=/") + 1).split("/");

answered Aug 12 '15 at 18:17

Ashraf Purno

1,065
6
11

m.cekiera · Answer 3 · 2015-08-12T18:30:28.560

Try with:

private void parseXpath() {
    String s = "path=/Some/Xpath/Here";
    s = s.replace("path=","");

    String[] tokens = s.split("/");
    for(String t: tokens){
        System.out.println(t);
    }
}

Also you can avoid removing it at all, if you get path=/Some/Xpath/Here by other regex, use lookbehind instead of exact matching:

(?<=path=)[^\\,]*

you should get just /Some/Xpath/Here.

EDIT If you want to print array as String, use static method Arrays.toString(yourArray);

score 1 · Answer 4 · answered Aug 12 '15 at 18:28

if you are looking into performance you should avoid usage of split since it uses regular-expressions which is a bit oversized for such a simple problem. if you just want to remove "path=" and you are sure that your string always starts that way you could go with the following:

String s = "path=/Some/Xpath/Here";
String prefix = "path=";
String result = s.substring(prefix.length);

How to remove all String text before equals ('=') sign Java

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