VALIDATE STRING XML in JAVA

Question

String strXML ="<?xml version='1.0' encoding='UTF-8' standalone='yes'?><custDtl><name>abc</name><mobNo>9876543210</mobNo></custDtl>"

how to validate whether the string is a proper XML String.

possible duplicate from http://stackoverflow.com/questions/6362926/xml-syntax-validation-in-java — Erwan C., Aug 13 '15 at 12:35
I am able to validate a XML File using SAXParserFactory and SAXParserException. but unable to parse String XML — user2019331, Aug 13 '15 at 12:43
Also I tried JAXB UnMarshaller for String XML Parsing & it is throwing SAXParserException i am not able to handle.. — user2019331, Aug 13 '15 at 12:47
Validating a string is not the same as validating a file, not a duplicate. — Adam Eberbach, Jun 29 '17 at 03:17

score 6 · Accepted Answer · answered Aug 13 '15 at 13:02

You just need to open an InputStream based on the XML String and pass it to the SAX Parser:

try {
    String strXML ="<?xml version='1.0' encoding='UTF-8' standalone='yes'?><custDtl><name>abc</name><mobNo>9876543210</mobNo></custDtl>";
    SAXParser saxParser = SAXParserFactory.newInstance().newSAXParser();
    InputStream stream = new ByteArrayInputStream(strXML.getBytes("UTF-8"));
    saxParser.parse(stream, ...);
} catch (SAXException e) {
    // not valid XML String
}

Thank You. just had to add SAX handler part. – user2019331 Aug 14 '15 at 05:32 — user2019331, Aug 14 '15 at 05:32

score 1 · Answer 2 · answered Feb 17 '21 at 10:45

public static boolean isXMLValid(String string) {
    try {
        SAXParserFactory.newInstance().newSAXParser().getXMLReader().parse(new InputSource(new StringReader(string)));
        return true;
    } catch (ParserConfigurationException | SAXException | IOException ex) {
        return false;
    }
}

VALIDATE STRING XML in JAVA

2 Answers2