Access objects in ordered default dict

Question

I am using an order default dict from here . The problem is that i don't know how to access the objects.

I am expecting that something like this should work

{% for zone in data %}
    {% for reservation in zone %}
        {{reservation}} # 1 | 2| 3
    {% endfor %}
{% endfor %}

Data to help the debug

{{data}}

OrderedDefaultDict(<type 'list'>, DefaultOrderedDict([('1', [<app.backoffice.models.Reservation object at 0x7f91c2c5ee10>, <app.backoffice.models.Reservation object at 0x7f91c2c732d0>, <app.backoffice.models.Reservation object at 0x7f91c2c73510>]), ('2', [<app.backoffice.models.Reservation object at 0x7f91c2c73790>, <app.backoffice.models.Reservation object at 0x7f91c32f9c50>]), ('3', [<app.backoffice.models.Reservation object at 0x7f91c2c733d0>, <app.backoffice.models.Reservation object at 0x7f91c2c73490>])]))

{% for zone in data %}
   {{zone}} # 1 | 2 | 3
   {{zone[0]}} # 1 | 2 | 3
{% endfor %}

Presumably just like you'd access the data in a plain `dict`. — juanchopanza, Aug 14 '15 at 11:44
What template language is this, Django templates, Jinja2, something else entirely? — Martijn Pieters, Aug 14 '15 at 11:46
And you expect something to work; what happened when you tried? Was there a specific error? — Martijn Pieters, Aug 14 '15 at 11:47
@MartijnPieters I just want to iterate the objects for each key. there is no error, my example just print the key. — user2990084, Aug 14 '15 at 11:48
@user2990084: right, because your keys are strings with just one character. `zone` is set to `'1'`, looping over that string gives you the character `'1'` (the only character in the string). Indexing to `zone[0]` gives you that same character. — Martijn Pieters, Aug 14 '15 at 11:53

Martijn Pieters · Accepted Answer · 2015-08-14T11:55:05.980

When you loop over a dictionary (even a subclass) you get keys; you'd have to translate that key into a value first if you want to loop over nested objects:

{% for zone in data %}
    {% for reservation in data[zone] %}
        {{reservation}}
    {% endfor %}
{% endfor %}

Since you don't display the zone key, you may as well loop over the dictionary values (using dict.itervalues() to avoid creating a redundant list object):

{% for reservations in data.itervalues() %}
    {% for reservation in reservations %}
        {{reservation}}
    {% endfor %}
{% endfor %}

or use dict.iteritems() to get both the key and the value:

{% for zone, reservations in data.iteritems() %}
    {{zone}}: 
    {% for reservation in reservations %}
        {{reservation}}
    {% endfor %}
{% endfor %}

In your own attempts, zone was only ever set to each key, which in your case are single-character strings ('1', '2' and '3'). Looping over a single-character string or indexing that string with zone[0] will only result in that one character to be shown.

Access objects in ordered default dict

1 Answers1