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I am trying to d file = new file (location) while location of file is absolute path with somethign like this : \\test\hold\REPO/TEST/Letter/123.pdf I am getting file not found exception while files are there in this path. what could be going wrong? can i have path with both forward and backward slash?

Amit Bhati
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Narayana
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  • Try to list all the files in the path using list method of File class to check whether file is actually present in the path or not ? If file exists then see the case of file name, even extension ? Problem is either the program is not taking the correct path or there is a mismatch between file name and what you have given in code. – Amit Bhati Aug 16 '15 at 03:49
  • Why are slashes different? – Mikhail Krutov Aug 16 '15 at 03:50
  • Please look into : `File.separator` variable. This answer might help you too : http://stackoverflow.com/questions/5971964/file-separator-or-file-pathseparator – Gyan Aug 17 '15 at 07:03

5 Answers5

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String separator = System.getProperty("file.separator"); So location can be rewritten to location=separator+"test"+separator+"hold"+separator +"REPO"+separator "TEST"+separator+"Letter"+separator+"123.pdf"; In this case no need to think about underlying OS

LONGHORN007
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You need two slashes in a string literal to represent one in the filename. Try

"\\\\test\\hold\\REPO/TEST/Letter/123.pdf"

or better still

"//test/hold/REPO/TEST/Letter/123.pdf"

There is never a need to use a backslash in a filename in Java.

user207421
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Try adding quotes around the filename.

Kip
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You can write your code without single backward slashes.if you want to use back-word slashes use \\ instead of \ .A single backward slashes create a problem if you put it inside the String literal.So you can write you code in multiple ways to avoid your exceptions. 

1)  File f=new File("\\test/hold/REPO/TEST/Letter/123.pdf");
2)  File f=new File("\\test\\hold\\REPO/TEST/Letter/123.pdf");
3)  File f=new File("\\test\\hold\\REPO\\TEST\\Letter\\123.pdf");
4)  File f=new File("/test/hold/REPO/TEST/Letter/123.pdf");
Pankaj Verma
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you can use :- InputStream input = new URL("\\test\hold\REPO/TEST/Letter/123.pdf").openStream(); or 

File file = new File(location);

where location=\\test\hold\REPO/TEST/Letter/123.pdf; and Check Using SOP statement whether URL is Call properly or not . hope it will help you to fine better solution

Anand Dwivedi
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