This is a beginner question, I have already checked that Check existence of input argument in a Bash shell script but it doesn't fully explain what I want to do.
gcc -Wall cx17.$1.c -o cx17.$1
if [ -z "$1" ]
then
echo "No argument supplied"
else if [ -z "$2"]
then
echo "Data file is missing!!"
else if [ -z "$3"]
then
./cx17.$1 $2 > ./cx17.$1.$2
else
./cx17.$1 $2 $3 > ./cx17.$1.$2
fi
So you understand this very basic use case, depending on arguments (if there is 1, 2 or 3) the script will perform a different task.
I know it's really simple that's why I think I'm missing something obvious.
Thanks for your help
The answered I validate gave me some errors but lead me to the right stuff:
if [ -z "$1" ]; then
echo 'No argument supplied';
elif [ -z "$2" ]; then
echo 'Data file is missing!!';
elif [ -z "$3" ]; then
./cx17.$1 $2 >./cx17.$1.$2;
else
./cx17.$1 $2 $3 >./cx17.$1.$2;
fi;