Remove " from regex result python

Question

So I've used this answer to get really close to what i need.

In my case I want to split on space but not when a part of the string is within quotes.

This is my code:

data = '"abc dfg" ab da'    
PATTERN = re.compile(r'''((?:[^ "']|"[^"]*"|'[^']*')+)''')
wordList = PATTERN.split(data)[1::2]

Gives wordList:

['"abc dfg"', 'ab', 'da']

How can I change the expression so that the string is without the extra quotes?

Like this:

['abc dfg', 'ab', 'da']

just replace quotes from the returned text with an empty string. — Avinash Raj, Aug 18 '15 at 13:08

score 5 · Accepted Answer · answered Aug 18 '15 at 13:09

You don't have to complicate your regex, simply iterate on the list and remove " from it. You can do that in many ways, for example using strip('"').

By the way, you have much better solution:

>>> import shlex
>>> shlex.split('"abc dfg" ab da')
['abc dfg', 'ab', 'da']

score 1 · Answer 2 · answered Aug 18 '15 at 13:08

1

>>> wordList = ['"abc dfg"', 'ab', 'da']
>>> wordList = [word.strip('"') for word in wordList]
>>> wordList
['abc dfg', 'ab', 'da']

answered Aug 18 '15 at 13:08

Kevin

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`[word.strip('"').strip("'") for word in wordList]` – Avinash Raj Aug 18 '15 at 13:09

Remove " from regex result python

2 Answers2