Python: Wrong output in sum of digits of a number

Question

I got wrong output when I run the programme.I use python 3.4.3 version.Below is my program code,

CODE:-

from pip._vendor.distlib.compat import raw_input

def sumOfDigits(n):
    summ=0;
    while(n!=0):
        r = n%10;
        summ+=r;
        n/=10;
    return summ;


input_num = raw_input("Enter a number : ");
n = int(input_num);

print("sum of digits of the number %s is %d" % (input_num,sumOfDigits(n)));

OUTPUT:-

Enter a number : 54928
sum of digits of the number 54928 is 31

@Amadan, you should make that an answer so OP can accept it. — Cyphase, Aug 19 '15 at 07:48

score 1 · Answer 1 · answered Aug 19 '15 at 07:51

1

TRY:

def sumOfDigits(n):
r = 0
while n:
    r, n = r + n % 10, n / 10
return r


input_num = raw_input("Enter a number : ");
n = int(input_num);

print("sum of digits of the number %s is %d" % (input_num,sumOfDigits(n)));

Worked for me perfectly.

answered Aug 19 '15 at 07:51

Ritobroto Mukherjee

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Python: Wrong output in sum of digits of a number

1 Answers1