Wrong code structure accepted by GCC/G++

Asked Aug 20 '15 at 20:58

Active Aug 20 '15 at 22:08

Viewed 103 times

Using the GCC/G++ compiler, I've used the following code structure for a long time and never had any problem with it:

if((int returnCode = function(argument1, argument2)) != 0) {
    manageTheError(returnCode);
}

I switched to Visual C++ 2015, but now my code throws many errors everytime I use this structure: (translated from french)

Syntax error: missing ')' before identifier 'returnCode' (line 1)
'returnCode': undeclared identifier (line 1)
Syntax error: '!=' (line 1)
Syntax error: ')' (line 1)
Syntax error: missing ';' before '{' (line 1)
')' was expected (line 1)
expression was expected (line 1)
'returnCode': undeclared identifier (line 2)
identifier 'returnCode' undefined (line 2)

As this question explains, my code structure is wrong and should not be used. But why does GCC/G++ accept it without complaining (not even a warning) and how does it manage these structures?

edited May 23 '17 at 12:06

Community

asked Aug 20 '15 at 20:58

Magix

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You may replace if's condition with `if(int returnCode = function(argument1, argument2))`, since it is equivalent form, that is valid in C++ and it's working in VS2013. – Grzegorz Szpetkowski Aug 20 '15 at 21:34
_"Never had any problem with it"_ [I do believe you're making that up](http://coliru.stacked-crooked.com/a/986c4955d2473c82). – Lightness Races in Orbit Aug 20 '15 at 21:37
Well in code::blocks it doesn't throw an error... – Magix Aug 20 '15 at 21:52
Don't tag questions as *both* C and C++ unless it really is. This is a C++ question if you're using MS C++ and G++. – Brian McFarland Aug 20 '15 at 22:08
`if(x)` is defined as equivalent to `if( x != 0 )` so (as Grzegorz noted already) you can solve your problem by just taking out the `!= 0`. – M.M Aug 20 '15 at 22:41

Wrong code structure accepted by GCC/G++

0 Answers0