Regular expression for parsing a phone number

Question

I need a regular expression for a phone number.

Example,

1234567899 should be (123)(456)(7899)
12345678 should be (123)(456)(78)
1234567 should be (123)(456)(7)
123456 should be (123)(456)
12345 should be (123)(45)
123 should be (123)
1 should be (1)

I tried /([0-9]{0,3})([0-9]{0,3})([0-9]{0,4})/ and /([0-9]{3})([0-9]{3})([0-9]{4})/

But it takes only when all the 10 numbers are in the input.

I need match then replace with (

What about international phone numbers? Always expect the unexpected! — Gary_W, Aug 21 '15 at 15:23

Blorgbeard · Accepted Answer · 2015-08-21T04:46:48.467

1

This would appear to work:

/(\d{1,3})(\d{1,3})?(\d{1,4})?/

Live test here

edited Aug 21 '15 at 04:46

answered Aug 21 '15 at 04:30

Blorgbeard

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how to add parenthesis? – alpha bravo Aug 21 '15 at 04:41
What language are you using? – Blorgbeard Aug 21 '15 at 04:45
Mule `datawaeve` and it use `lambda` – Sahal Aug 21 '15 at 04:50

KAD · Answer 2 · 2015-08-21T04:43:40.623

1

Check this : /^$\d{0,3}$($\d{0,3}$)?($\d{0,4}$)?$/

https://regex101.com/r/qC0fS9/2

edited Aug 21 '15 at 04:43

answered Aug 21 '15 at 04:32

KAD

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This would appear to match the brackets? OP has the raw digits, and wants to add brackets. Also, no need for `[]` around `\d`. – Blorgbeard Aug 21 '15 at 04:37
Yeah I updated the regex and removed `[]`, From my understanding I though he wanted to look for the brackets.. Anyway the question has an answer now.. – KAD Aug 21 '15 at 04:50

alpha bravo · Answer 3 · 2015-08-21T05:04:41.210

1

use this pattern

((^\d{1,3})|(?<=^\d{3})(\d{1,3})|(\d+$))

or simplified to

(^\d{3}|(?<=^\d{3})\d{3}|\d+$)

and replace with (\1)

Demo

edited Aug 21 '15 at 05:04

answered Aug 21 '15 at 04:38

alpha bravo

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Regular expression for parsing a phone number

3 Answers3