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I am using grep recursive to search files for a string, and all the matched files and the lines containing that string are print on the terminal. But is it possible to get the line numbers of those lines too??

ex: presently what I get is /var/www/file.php: $options = "this.target", but what I am trying to get is /var/www/file.php: 1142 $options = "this.target";, well where 1142 would be the line number containing that string.

Syntax I am using to grep recursively is sudo grep -r 'pattern' '/var/www/file.php'

One more question is, how do we get results for not equal to a pattern. Like all the files but not the ones having a certain string?

Du-Lacoste
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sai
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7 Answers7

677
grep -n SEARCHTERM file1 file2 ...
Dominykas Mostauskis
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Miro A.
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    I had another quick question, how do we get results for not equal to a pattern. Like all the files but not the ones having a certain string? – sai Jul 09 '10 at 15:23
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    that would be command line switch -v. If you run 'grep --help' it will display all options – Miro A. Jul 09 '10 at 16:05
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    You don't need `-r` if you specify multiple files. You only need `-r` if you specify directories. – Sparhawk Oct 21 '15 at 10:10
  • @JeanPaul - I see same result for both -nr and -n -r. What version of grep are you using ? $ grep -n -r name * | wc -l 1984 $ grep -nr name * | wc -l 1984 $ grep -V grep (BSD grep) 2.5.1-FreeBSD – Miro A. Mar 09 '18 at 10:47
  • Code only answer, no explanation. :S – Itération 122442 Apr 02 '20 at 09:35
181

Line numbers are printed with grep -n:

grep -n pattern file.txt

To get only the line number (without the matching line), one may use cut:

grep -n pattern file.txt | cut -d : -f 1

Lines not containing a pattern are printed with grep -v:

grep -v pattern file.txt
carlodef
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    And last matching line number: `grep -n pattern file.txt | cut -d : -f 1 | tail -1` (you can save this to a variable and use it to e.g tail file from it) – Nux May 07 '14 at 14:08
  • And to remove the number/colon at the beginning of each string you can use something like: `grep -n pattern file.txt | sed 's/^[0-9][0-9]*://'` – leetbacoon Aug 05 '19 at 00:02
31

If you want only the line number do this:

grep -n Pattern file.ext | gawk '{print $1}' FS=":"

Example:

$ grep -n 9780545460262 EXT20130410.txt | gawk '{print $1}' FS=":" 
48793
52285
54023
quotesBro
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Cloud Falls
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13
grep -A20 -B20 pattern file.txt

Search pattern and show 20 lines after and before pattern

fedorqui
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emilio
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2

grep -nr "search string" directory

This gives you the line with the line number.

gorkem
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randomguy
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2

In order to display the results with the line numbers, you might try this

grep -nr "word to search for" /path/to/file/file 

The result should be something like this:

linenumber: other data "word to search for" other data
Fuad Fouad
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0

When working with vim you can place

function grepn() {
    grep -n $@ /dev/null | awk -F $':' '{t = $1; $1 = $2; $2 = t; print; }' OFS=$':' | sed 's/^/vim +/' | sed '/:/s// /' | sed '/:/s// : /'
}

in your .bashrc and then

grepn SEARCHTERM file1 file2 ...

results in

vim +123 file1 : xxxxxxSEARCHTERMxxxxxxxxxx
vim +234 file2 : xxxxxxSEARCHTERMxxxxxxxxxx

Now, you can open vim on the correspondending line (for example line 123) by simply copying vim +123 file1 to your shell.

Porsche9II
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