Why does Bash wrap this output line onto itself?

Question

I've got a file that holds a token:

$ cat .token
token="35aaac83-cd67-5ced-a3b5-00c388f725c5"

I am trying to use this file inside a Bash function:

func() {

    . .token

    local payload='{                                                                                                                                                                                    
        "jsonrpc": "2.0",                                                                                                                                                                               
        "method": "listFile",                                                                                                                                                                           
        "params": [ "'"$token"'", "/" ],                                                                                                                                                                
        "id": 1                                                                                                                                                                                         
    }'    

    echo "$payload"
}

When I run this function, the output is:

{
        "jsonrpc": "2.0",
        "method": "listFile",
", "/" ],params": [ "35aaac83-cd67-5ced-a3b5-00c388f725c5
        "id": 1
    }

As you can see, the line with params gets wrapped onto itself. I can't figure out why. I've been able to ascertain this has something to do with the . sourcing of the $token: when I hardwire $token, everything works fine. What's that matter here?

@thrig Heh, indeed the ending chars are `0d0a`. I did this, but somehow missed this on the first time around. Thank you. Please feel free to post an answer. — Dmitry Minkovsky, Aug 24 '15 at 15:09
@thrig: if you could explain why the `CRLF` causes a wrap though... — Dmitry Minkovsky, Aug 24 '15 at 15:10
The `\r` means "go back to the start of the line", which will then cause it to overwrite anything else on that line. I bet there is only a `\r` in `$token` and the `\n` is from somewhere else — Eric Renouf, Aug 24 '15 at 15:29

Why does Bash wrap this output line onto itself?

0 Answers0