7

I have a "Duplicate entry" exception, which logging SqlExceptionHelper. I need to disable logging only this exception. How can I do it?

Squeez
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3 Answers3

7

I am assuming you are using Log4j for your logging. You may want to explore ExpressionFilter.

I am appending a sample configuration, you can take it from there, hopefully.

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE log4j:configuration SYSTEM "log4j.dtd">
<log4j:configuration xmlns:log4j="http://jakarta.apache.org/log4j/" debug="false">
    <appender name="CONSOLE">
        <param name="Target" value="System.out"/>
        <layout>
            <param name="ConversionPattern" value="%d %p [%c] - %m%n"/>
        </layout>
        <filter class="org.apache.log4j.filter.ExpressionFilter">
            <param name="expression" value="EXCEPTION ~= SqlExceptionHelper" />
            <param name="acceptOnMatch" value="false"/>
        </filter>
    </appender>
    <root>
        <priority value ="INFO" />
        <appender-ref ref="CONSOLE"/>
    </root>
</log4j:configuration>
informatik01
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user1933888
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2

If you are using log4j2

<Logger name="org.hibernate.engine.jdbc.spi.SqlExceptionHelper" level="OFF" additivity="false">
     <AppenderRef ref="Console" />
</Logger>
abbas
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-7

You can catch the exception and do nothing

try {                                              
      method();      

    } catch(ConstraintViolationException  e){}    
Bruno Caceiro
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