How to show a php page in the html page that called it?

Question

I'm new to php and html, so I'm not sure that the title is easy to understand, sorry for that. The problem is simple , I have an html form like this:

<form action="action_calibration.php" method=post>
  <br><br>
  <input type="radio" name="type" value="fast" checked>Fast Calibration
  <br><br>
  <input type="radio" name="type" value="old">Old Calibration
  <br><br>
  <input type="checkbox" name="ScanVPlus" value="yes" checked>Scan 
  <br><br>
  <input type="checkbox" name="Bitwise" value="yes">Bitwise Offset 
  <br><br>
  <input type="checkbox" name="All_channel" value="yes">Calibration 
  <br><br>
  Output Folder:<input type="textfield" name="output" value="Results/">
  <br><br>
  Hw Description File:<input type="textfield" name="Hw Description File " value="settings/Calibration2CBC.xml">
  <br><br>
  <input type="submit" value="Submit">
  </form>

The action_calibration.php is a php page that execute a binary file and show the results on the php page, what I'm tring to do is print these results on the page containing the form, without open another one. I hope that you can understand what I mean. Thank you.

Sounds like you need to search around a bit for ajax and php, and read some tutorials. — Joel Hinz, Aug 26 '15 at 16:01

score 2 · Accepted Answer · edited May 23 '17 at 11:51

2

Try including an iframe sibling the form, with a name, and giving the form a target attribute.

Related: How do you post to an iframe?

edited May 23 '17 at 11:51

Community

1
1

answered Aug 26 '15 at 16:11

robermorales

3,293
2
27
36

Thank you this was exactly what I was looking for – user3050386 Aug 26 '15 at 16:34

How to show a php page in the html page that called it?

1 Answers1