Is there's any difference between char
literals '\"'
and '"'
?
Asked
Active
Viewed 1,493 times
2

polygenelubricants
- 376,812
- 128
- 561
- 623

user388989
- 61
- 1
- 1
- 3
-
Ummm ... it would have taken 30 seconds to test it yourself. – Stephen C Jul 11 '10 at 22:06
1 Answers
9
There is absolutely no difference. The two char
are ==
.
System.out.println('\"' == '"'); // prints "true"
Strictly speaking it's not necessary to escape a double quote in a char
literal, but it doesn't change this fact that \"
denotes the double quote character \u0022
.
References
String
analog
We also have the analogous situation for String
literals:
System.out.println("\'".equals("'")); // prints "true"
In fact, we can even go a step further and use ==
for reference equality:
System.out.println("\'" == "'"); // prints "true"
The second snippet proves that the two string literals are really equal, and therefore subject to string interning at compile-time.
References
- JLS 3.10.5 String Literals
String literals --or, more generally, strings that are the values of constant expressions-- are "interned" so as to share unique instances, using the method
String.intern
.
Related questions
- How do I compare strings in Java?
- Java
String.equals
versus==
- Where do Java and .NET string literals reside?
- When
“” == s
isfalse
but“”.equals( s )
istrue
Summary
- A single-quote in a
char
literal MUST be escaped- Because
char
literal is quoted in single-quotes
- Because
- A double-quote in a
String
literal MUST be escaped- Because
String
literal is quoted in double-quotes
- Because
- It doesn't hurt to escape, even when it's not necessary
- Go with what's most readable

Community
- 1
- 1

polygenelubricants
- 376,812
- 128
- 561
- 623