Python increment string with both letters and numbers

Question

I am attempting to increment a string that has both letters and numbers in it - each of the characters in the string can either be 0-9 or a-z, no upper case letters.

Ideally I would hope it could be incremented in a +1 fashion in the sense that if the string was o6 to o7 o8 o9 oa ob etc to oz then p0 p1 etc by the way that's a lower base O not a zero

The method I use to increment only works by converting string to int, then incrementing by +1 and cannot be used here.

number = str(int(number) + 1)

So, you only want to increment the second character? And what happens for a `9` or `z`? — TigerhawkT3, Aug 27 '15 at 23:45
I appreciate you greatly tigerhawk - the duplicate you found was part of what I needed, in defining baseencode and decode for 36 - but the answer is listed below as number = base36encode(base36decode(number) + 1) ty though for sure — In the stars, Aug 28 '15 at 00:30

score 1 · Accepted Answer · edited May 23 '17 at 11:43

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This question shows you how to do base36 encoding/decoding in Python.

To increment a number that is encoded in base36, you just decode it to an integer, add 1, then encode the result.

number = base36encode(base36decode(number) + 1)

edited May 23 '17 at 11:43

Community

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answered Aug 27 '15 at 23:52

Alasdair

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Your answer did it for me - the duplicate helped me define the two and number = base36encode(base36decode(number) + 1) did the rest, thanks so much – In the stars Aug 28 '15 at 00:32

Python increment string with both letters and numbers

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