jaava NullPointerException

Asked Aug 28 '15 at 07:24

Active Aug 28 '15 at 07:24

Viewed 57 times

        class Process 
        {
          int PID;
        }

        Process[] processes = new Process[n];

        for(int i=0;i<n;i++)
        {
            System.out.println("Enter PID for process " + (i+1) );
            >>>processes[i].PID = Integer.parseInt(br.readLine());
        }

I got the exception in ">>>" What am i doing wrong?

asked Aug 28 '15 at 07:24

kiddie

1

What's `br`? How do you initialise it? – MadProgrammer Aug 28 '15 at 07:25
1

Process[] processes = new Process[n]; Look at the code, you just created an array of processes and you never put anything in that array. – Suresh Atta Aug 28 '15 at 07:26
You are creating an Array of processes, with 10 references to an actual `Procees`, which need to be initzialized first. – SomeJavaGuy Aug 28 '15 at 07:26
@KevinEsche can you tell me how to initialize? :) – kiddie Aug 28 '15 at 07:56
@KevinEsche i tried processes[0].PID = 0; but the exception switch to that line when run – kiddie Aug 28 '15 at 08:43
@kiddie write `processes[i] = new Process()` before you try to assign `PID` – SomeJavaGuy Aug 28 '15 at 09:09

jaava NullPointerException

0 Answers0