how to get parameters in php page with ajax and $.post

Question

actually i'm new to web and php, i'm building a website, i would like to introduce chat session there but, when the user click the insert button that's not working (failing to pass the paramerts to another page)

Help me out...!!!

here is the code

chat_page.php

<input type="text" id="txtmsg" name="txtmsg" size="25"> <input type="button" value="send" onclick="sndmsg()">

jscript.js

function sndmsg() {
    msg=document.getElementById('txtmsg').value;
    $.post("insert.php",{u:un,m:msg},function(){ });
    document.getElementById('txtmsg').value=""; 
}

insert.php

include("connec.php");
$chatmsg=mysql_real_escape_string($_REQUEST['m']);
$uname=mysql_real_escape_string($_REQUEST['u']);
echo $chatmsg;
echo $uname;
mysql_query("INSERT INTO `mdi_chat_msg`(`uname`, `chatmsg` ) VALUES ( '$uname','$chatmsg')") or die(mysql_error());

Check your developers console and see if you find any errors.. — Rayon, Aug 29 '15 at 09:11
Have you declared the variables `un` and `msg` anywhere in your JS code? (something along the lines of `un='user'; msg = $('#txtmsg').val();` ? — uri2x, Aug 29 '15 at 09:17
please do not use mysql extension anymore, as it's [deprecated the the moment](http://stackoverflow.com/questions/12859942/why-shouldnt-i-use-mysql-functions-in-php) and is going to be [removed in PHP7 completely](https://wiki.php.net/rfc/remove_deprecated_functionality_in_php7) — Zathrus Writer, Aug 29 '15 at 09:20
Now i got the answer, its the problem with the request values. Thanks to everyone. Cheers. — Md Ghouse Saqlain, May 27 '16 at 10:53

score 1 · Accepted Answer · answered Aug 29 '15 at 09:20

1

What is un in jscript.js. Maybe, that parameter is unknown.

$.post("insert.php",{u:un,m:msg},function(){ });

You should declare un and msg variables;

var un, msg;

answered Aug 29 '15 at 09:20

Sherali Turdiyev

1,745
16
29

Actually I haven't assigned the values. – Md Ghouse Saqlain May 27 '16 at 10:55

score 0 · Answer 2 · edited Aug 29 '15 at 12:21

0

Check you have declare and change the type="submit" instead type="button" you cant use the word msg as variable and cant pass the js value in ajax and check un variable.

<form>
   <input type="text" id="txtmsg" name="txtmsg" size="25"> <input type="submit" value="send" onclick="sndmsg()">
</form>


<script>
    function sndmsg() {
        msg1=$("#txtmsg").val();
        $.post("insert.php",{u:un,m:msg},function(){ });
        document.getElementById('txtmsg').value=""; 
    }
    $.ajax({
        type: "POST",
        url: "insert.php",
        data: { u: un,m:msg1},
    });
</script>

edited Aug 29 '15 at 12:21

Abdallah Alsamman

1,623
14
22

answered Aug 29 '15 at 09:18

user3386779

6,883
20
66
134

form? why? He is use ajax ? why you think can solve problem with this solution? – A1Gard Aug 29 '15 at 09:20

how to get parameters in php page with ajax and $.post

2 Answers2