C# - How can I make a 'chance of success' method

Question

I've been learning c# and I want to start an experimental console application project of an American Football Simulator. It is vital for this project to have chances.

Example: there's a 20% chance the kicker will succeed in a field goal kick over 45 yards.

I've looked around on here and noticed people using randoms, but is that really the most efficient way to go about doing this?

Random chance = new Random(1, 100);
If (Yards > 45)
{
    If (chance <= 20)
    {
        // Field goal success
    }
    else
    {
        // Field goal fail
    }
}

What would be the best way to go about doing this?

`new Random` is not. Create it just once. And learn how to use its Next() method. — Hans Passant, Aug 29 '15 at 11:50

score 1 · Answer 1 · edited Aug 29 '15 at 13:18

1

It's very simple. Just do this:

private Random _rnd = new Random();
public bool RandomSuccess(double probability)
{
    return _rnd.NextDouble() < probability;
}

Then use it like this:

if (Yards > 45)
{
    if (RandomSuccess(0.2))
    {
        // Field goal success
    }
    else
    {
        // Field goal fail
    }
}

edited Aug 29 '15 at 13:18

Aheho

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answered Aug 29 '15 at 12:19

Enigmativity

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1

You cannot pass a double to a method that expects a boolean. – Cetin Basoz Aug 29 '15 at 12:53
1

I'm getting an error that the operator cannot be applied to operands of type double and bool – Donavon Aug 29 '15 at 13:01
@Donavon maybe you should *understand* the answer and then fix the trivial mistake that has been made. – usr Aug 29 '15 at 13:20
@usr, people simply downvote without understanding a solution. It is normal to quote on mistakes. – Cetin Basoz Aug 29 '15 at 13:32
@Ahelo - Thanks for the fix. – Enigmativity Aug 30 '15 at 02:27

C# - How can I make a 'chance of success' method

1 Answers1