<?php
$name=$_POST['name'];
$telephone=$_POST['telephone'];
$comment=$_POST['comment'];
$conn= mysql_connect("localhost","root","");
mysql_select_db("comments",$conn);
$sql= "INSERT INTO inside VALUES{($_POST['name']),($_POST['telephone']),($_POST['comment'])}";
if(mysql_query($sql,$conn))
{
echo 'record added';
}
else
{
echo 'error';
}
?>
I don't know what is the error in line 10, line 10 is:
$sql= "INSERT INTO inside VALUES{($_POST['name']),($_POST['telephone']),($_POST['comment'])}";
My database name is comments and table name is inside, and also sometimes when I finished this I got the result as 'error' I think it comes from the line 18. can you please tell me how to solve this, I'am fed of this!