Java - Fields vs implemented Methods

Question

I have to parse a JSON response and return objects which holds its data. But I am not sure which solution is more "memory-friendly":

Method 1: Fields

public class MyElement {

    private int var1;

    public MyElement(int var1) {
        this.var1 = var1;
    }

    public int getVar1() {
        return var1;
    }

}

Method 1.1: Direct access on field.
Method 1.2: Using builders/factories.

Method 2:

public interface MyElement {
    int getVar1();
}

// In Code
return new MyElement() {
    @Override
    public int getVar1() {
        return 5;
    }
}

I wouldn't write such a thing: Use Jackson. It requires that your objects follow the Java Bean standards. Don't worry about memory friendly until you've profiled your app and data tells you there's a problem. — duffymo, Sep 05 '15 at 15:23

score 0 · Answer 1 · answered Sep 05 '15 at 15:25

Side note: public getVar1() does not compile. Any difference between methods 1, 1.1 and 1.2 is negligible (though 1.1 is mutable unless you make your field final), but I would use method 1. This is because, with method 2, a new (anonymous) class is actually created. If this is executed many times, tons of classes are created. Of course, such differences usually wouldn't matter unless on a truly massive scale, so don't make memory an issue when it isn't one.

score 0 · Answer 2 · edited May 23 '17 at 12:19

0

I think the Java Bean Standard is a better approach as it followed in most of the implementations in software development.

I have good references links for you below which will explain details about your doubts :

Places where JavaBeans are used?

When would you use the Builder Pattern?

edited May 23 '17 at 12:19

Community

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answered Sep 05 '15 at 16:01

Ashish Shukla

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Java - Fields vs implemented Methods

2 Answers2