In Python, my String Comparisons are ALWAYS Coming Back False:

Question

For some reason, all of my "if's" and "elif's" come back true no matter what

nyornj = raw_input("select ny or nj please")
newyork="NY" or "nj"
newjersey="NJ" or "nj"
if nyornj==newyork:
    print "New York was input"
if nyornj==newjersey:
    print "New Jersey was input"

Nothing seems to be working, any ideas why this would always come back true?

It's short circuiting to the first condition so it's always comparing to `"NY" or "NJ"`, you could've tested this if you'd printed out `newyork` and `newjersey`, anyway it makes more sense to uppercase or lowercase your input and test against a single value — EdChum, Sep 08 '15 at 12:21
ah I see, is there any way to not have this happen but keep the two pairs of "or's"? — driedupsharpie, Sep 08 '15 at 12:22
Why do you need `or`? just uppercase or lowercase every thing and test against a single str representation — EdChum, Sep 08 '15 at 12:23

Ahsanul Haque · Answer 1 · 2015-09-08T12:27:09.640

0

Instead of comparing with two different value, use str.lower() to convert to all lowercase and then compare.

nyornj = raw_input("select ny or nj please")
newyork="ny"
newjersey="nj"
if nyornj.lower()==newyork:
    print "New York was input"
if nyornj.lower()==newjersey:
    print "New Jersey was input"

edited Sep 08 '15 at 12:27

answered Sep 08 '15 at 12:20

Ahsanul Haque

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returns: SyntaxError: can't assign to operator – driedupsharpie Sep 08 '15 at 12:21
edited, should work now – Ahsanul Haque Sep 08 '15 at 12:28

In Python, my String Comparisons are ALWAYS Coming Back False:

1 Answers1