Java Syntax: Code block after semicolon?

Asked Sep 08 '15 at 14:35

Active Sep 08 '15 at 14:48

Viewed 47 times

I'm programming android for a while and it's first time i see this syntax:

private void createMenu(Menu menu)
{
    MenuItem mnu1 = menu.add(0, 0, 0, "Item 1");
    {
        menu1.setAlphabeticShortcut('a');
        menu1.setIcon(R.drawable.ic_launcher);
    }
}

After that line 3 is closed by a semicolon, at line 4 we see a block of code. what kind of syntax is it?

asked Sep 08 '15 at 14:35

hayden

3

See this: http://stackoverflow.com/questions/1563030/anonymous-code-blocks-in-java – Luis Alves Sep 08 '15 at 14:37
First of all mnu1 is misspelled. Second... why are you open { if you don't have a if statement, listener, method, etc? is unnecessary. – Mariano Zorrilla Sep 08 '15 at 14:38
Sorry re-opened by mistake. Closing again. – Mena Sep 08 '15 at 14:48

Java Syntax: Code block after semicolon?

0 Answers0