Why is there ... in a java function?

Question

I'm following a java tutorial named "Java Swing first programs" and I noticed something that troubles me. At one point, there's a function written like this:

private void createLayout(JComponent... arg)

I was wandering why there was a ... and what those it do?

The tutorial: http://zetcode.com/tutorials/javaswingtutorial/firstprograms/

check varargs in java – Raman Shrivastava Sep 08 '15 at 20:21 — Raman Shrivastava, Sep 08 '15 at 20:21

score 0 · Accepted Answer · answered Sep 08 '15 at 20:22

0

See the documentation for Java varargs.

answered Sep 08 '15 at 20:22

David Loewy

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http://stackoverflow.com/questions/766559/when-do-you-use-varargs-in-java – David Loewy Sep 08 '15 at 20:23

Why is there ... in a java function?

1 Answers1