Javascript, How to send a placeholder variable to a function?

Question

I have a function with an if-statement. When this if-statement is triggered I want to tell another function to clear out its array.

function firstFunction(){
    if(!$myCheckBox.is(':checked')){
        secondFunction(myArray.length = 0);
    }
}

function secondFunction(myArray){
    if(myArray.length == 0){
        //Do something
    }
}

Just send 0 as an argument. if you need `results` array also inside the function then send it too.. llike in the following `renderResults(0,results)` — Rajesh kannan, Sep 09 '15 at 08:14
Simply sending 0 to the array wont work, as it does not clear out the array. And sending [] will just create a new array right? Well, I want the same array to remain, but I want to clear it of any rows within. — Reality-Torrent, Sep 09 '15 at 08:17
[How to clear an array in JavaScript?](http://stackoverflow.com/questions/1232040/how-to-empty-an-array-in-javascript) — Anders, Sep 09 '15 at 08:21

Peter Kalef ' DidiSoft · Accepted Answer · 2015-09-09T10:07:28.007

1

The renderResult function expects the placeholder variable. You shall send it like this:

$('#randomName').change(function() {
if(!$randomName.is(':checked')){
            // modify [results] if needed, e.g. results.length = 0;
            renderResults(results);

edited Sep 09 '15 at 10:07

answered Sep 09 '15 at 08:18

Peter Kalef ' DidiSoft

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Please do not use code snippets for code not intended to actually run without extra context. Clicking run here just produce a syntax error. You can just use a code block without the run button instead. Thanks! – Anders Sep 09 '15 at 08:20

Javascript, How to send a placeholder variable to a function?

1 Answers1