MVC partial View and controller code

Question

I don't understand how a partial view is handled by controller, is it the same as a view? I made an example and it seems that partial view controller is never used

This is the example

Main View (test.cshtml):

<h2>Main View</h2>
@Html.Partial("_Partial", new { myNumber = 11 })

Partial View (_Partial.cshtml):

<h3>partial view</h3>
<p>my number is @Html.ViewBag.myNumber</p>

Controller (EtlMessagesController)

public ActionResult Test() {
    return View();
}

public ActionResult _Partial(int myNumber) {
    ViewBag.myNumber = myNumber;

    return PartialView();
}

When i invoke the main view I expect

Main View

partial view

my number is 11

But the nummber 11 is not written. Am I missing something?

it's just an example to understand why partial view controller is not invoked. In my scenario the partial view neet to get a list of model objects and render a part of them — Naigel, Sep 10 '15 at 12:11
`@Html.Partial()` does not call a controller method - it just renders the html defined in the view named `"_Partial"`. You need `@Html.Action("_Partial", new { myNumber = 11 })` to call a server method and render the html it generates — , Sep 10 '15 at 12:12

score 3 · Answer 1 · answered Sep 10 '15 at 12:13

3

Here your pass anonymous model to the partial view:

<h2>Main View</h2>
@Html.Partial("_Partial", new { myNumber = 11 })

Try use explicit model class or just int:

<h2>Main View</h2>
@Html.Partial("_Partial", 11)

Then you can use @model keyword in the partial view:

@model int
<h3>partial view</h3>
<p>my number is @Model</p>

As for:

public ActionResult _Partial(int myNumber) {
    ViewBag.myNumber = myNumber;

    return View();
}

You should use:

public ActionResult _Partial(int myNumber) {
    return PartialView("_Partial", 11);
}

The method PartialView can be used in AJAX scenarios to render a part of a HTML-page.

answered Sep 10 '15 at 12:13

Mark Shevchenko

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ad what if my partial view already have a model? Let's say it has @model `myCustomClass`, and i need an integer parameter `public ActionResult _Partial(int myNumber) { ...my code }` – Naigel Sep 10 '15 at 12:25
F.e. `_Partial(new myCustomClass { integerField = myNumber })`. – Mark Shevchenko Sep 10 '15 at 12:27
thank you, the problem was slightly different but your example helped a lot – Naigel Sep 10 '15 at 12:36

score 1 · Accepted Answer · edited May 23 '17 at 12:31

I found 3 ways thank to comments and answers:

@Html.Action (thank to Stephen Muecke comment on question)

@Html.Partial() does not call a controller method - it just renders the html defined in the view named "_Partial". You need @Html.Action("_Partial", new { myNumber = 11 }) to call a server method and render the html it generates

Using a ViewDataDictionary (thanks to Mark Schevchenko answer and this answer on another question)

@Html.Partial("_Partial", new { myNumber = 11 }) pass the second argument as the model, to pass parameters to controller ViewDataDictionary should be used instead

@Html.Partial("_Partial", new ViewDataDictionary { { "myNumber", 11 } }

Use the integer as partial view model (thanks to Mark Schevchenko answer)

See Mark Schevchenko answer. The cons of this way is that you can't have another model on your partial view

MVC partial View and controller code

2 Answers2