For loop running only once in Bash

Question

I've just started shell scripting. Here is my code:

read totalNumbers

for i in {1..$totalNumbers..1}
do
  echo "Welcome $i times"   
done

When the input is given as 100, I'm getting the output as

Welcome {1..100..1} times

But I need something like

Welcome 1 times

Welcome 2 times

Welcome 3 times

.

.

.

Welcome 100 times

Answer 1

You cannot use variable names inside {..} in shell.

You can use ((..)) for arithmetic in BASH:

for (( i=1; i <= $totalNumbers; i++ )); do
  echo "Welcome $i times"   
done

Even for (( i=1; i <= totalNumbers; i++ )) would work.

Answer 2

If you want to use

{1..$totalNumbers..1}

anyway, replace it by

$(eval echo {1..$totalNumbers..1})

---

$(...) runs a subshell.