I'm getting compilation error even though everything seems to be right

Question

I was trying to make a simple C program which, given X and Y coordinates, tells the quadrant. I'm getting an error:

cordinate.c: In function ‘main’:
cordinate.c:28:1: error: expected ‘;’ before ‘{’ token

As far as I know syntax-wise i's correct.

Code:

#include <stdio.h>
void main() {
    int x, y;

    printf("enter the cordinate x and y\n");
    scanf("%d%d",&x,&y);

    if ((x > 0) && (y > 0)) {
        printf("The point lies in 1st quadrant \n");
    } else if ((x < 0) && (y > 0)) {
        printf("The point lies in 2nd quadrant \n");
    } else if ((x < 0) && (y < 0)) {    
        printf("The point lies in 3rd quadrant \n");
    } else ( (x>0) && (y<0) )

    {   
        printf("The point lies in 4th quadrant \n");
    }
}

And when I do whatever is said I get the output as

input 
22
33
output
The point lies in 1st quadrant 
The point lies in 4th quadrant

Can anyone explain this?

Why do people show error messages including line numbers and do not refer to these numbers in the code they show? — alk, Sep 13 '15 at 10:39

score 4 · Accepted Answer · answered Sep 13 '15 at 10:30

4

 else ( (x>0) && (y<0) )
 {   
       printf("The point lies in 4th quadrant \n");
  }

else doesnt take any condition. Use

 else if ( (x>0) && (y<0) )

or only else .

answered Sep 13 '15 at 10:30

Sourav Kanta

2,727
1
18
29

Thanks a lot I got the output. – Akshdeep Sep 13 '15 at 10:44

score 2 · Answer 2 · answered Sep 13 '15 at 10:30

After else there is no conditions, fix your program like this:

 #include<stdio.h>
  void main()
 {
    int x,y;

    printf("enter the cordinate x and y\n");
    scanf("%d%d",&x,&y);

    if((x>0) && (y>0))
    {
        printf("The point lies in 1st quadrant \n");
    }  
    .
    .
    .

    else   // The condition removed form here
    {   
        printf("The point lies in 4th quadrant \n");
    }
}

else means that if all conditions fails then it will execute what is after else so there no need to specify condition after it.

Thanks a lot for ur help I got the output. – Akshdeep Sep 13 '15 at 10:50 — Akshdeep, Sep 13 '15 at 10:50

score 2 · Answer 3 · edited May 23 '17 at 11:58

2

It looks like you're missing an if keyword on this line:

} else ( (x>0) && (y<0) )

Also, you shouldn't use void main(). You can only use either int main(void) or int main(int argc, char **argv).

edited May 23 '17 at 11:58

Community

1
1

answered Sep 13 '15 at 10:30

Functino

1,939
17
25

Thanks I m a beginner in c and I didn't knew about this thanks a lot for ur help – Akshdeep Sep 13 '15 at 10:46

I'm getting compilation error even though everything seems to be right

3 Answers3