counting the number of vowels in a word in a string

Question

I am a beginner, and I am trying to find out the number of vowels in each word in a string. So for instance, if I had "Hello there WORLD", I want to get an output of [2, 2, 1].

Oh, and I am using Python.

I have this so far

[S.count(x) in (S.split()) if x is 'AEIOUaeiou']

where S="Hello there WORLD"

but it keeps saying error. Any hints?

possible duplicate of [Count occurrence of a character in a string](http://stackoverflow.com/questions/1155617/count-occurrence-of-a-character-in-a-string) — Andy, Sep 13 '15 at 19:32
`[sum(1 for char in word if char.lower() in set('aeiou')) for word in string.split()]` — Peter Wood, Sep 13 '15 at 19:36

score 1 · Answer 1 · answered Sep 13 '15 at 19:49

x is 'AEIOUaeiou'

This tests whether x is precisely the same object as 'AEIOUaeiou'. This is almost never what you want when you compare objects. e.g. the following could be False:

>>> a = 'Nikki'
>>> b = 'Nikki'
>>> a is b
False

Although, it may be True as sometimes Python will optimise identical strings to actually use the same object.

>>> a == b
True

This will always be True as the values are compared rather than the identity of the objects.

What you probably want is:

x in 'AEIOUaeiou'

score 0 · Accepted Answer · answered Sep 13 '15 at 21:11

0

Obviously, S in S.count and S in S.split cannot be the same S. I suggest using more semantic names.

>>> phrase = 'Hello there WORLD'
>>> [sum(letter.casefold() in 'aeiouy' for letter in word) for word in phrase.split()]
[2, 2, 1]

answered Sep 13 '15 at 21:11

Veky

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counting the number of vowels in a word in a string

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