Divide dictionary value(s) by integer value

Asked Sep 14 '15 at 15:22

Active Sep 14 '15 at 15:25

Viewed 442 times

I have a dictionary with only one entry (key names are varying and I don't know them) and want to divide the value by another integer value.

Since dict.values() only delivers dict views which were not suitable for a division, my workaround was to convert the dictionary value into a list and getting the element by its index:

in_max = {'b_el': 100000}
soc_max = 700000
c_rate_in = [in_max[k] for k in in_max][0] / soc_max

print(c_rate_in)
0.14285714285714285

But this solution seems to be a bit heavy-handed to me and also does not look very nice.

Is there a smarter way to get the same result?

edited Sep 14 '15 at 15:25

asked Sep 14 '15 at 15:22

Cord Kaldemeyer

6,405
8
51
81

If there is only one entry, why not just use `in_max['b_el']`? – Martijn Pieters Sep 14 '15 at 15:23
PS: I know that I could also access the dict element by its key. But the difficutly is that the keys may vary and I don't know their names.. – Cord Kaldemeyer Sep 14 '15 at 15:24
Wow, you were faster.. ;-) – Cord Kaldemeyer Sep 14 '15 at 15:24
I'll add it to my question.. – Cord Kaldemeyer Sep 14 '15 at 15:25
Oh, I haven't seen that this already had been asked for. `next(iter(in_max.values()))` did the job for me! – Cord Kaldemeyer Sep 14 '15 at 15:36

Divide dictionary value(s) by integer value

0 Answers0