binary value comes wrong after & with 0x000000FF

Asked Sep 15 '15 at 06:34

Active Sep 15 '15 at 06:34

Viewed 58 times

In the code below which is part of a tutorial found, i thought that ater running it the expected result of byte0 would be the same value as of int, 190:

int i = 190;
byte byte0 = (byte)((i & 0x000000FF));

Though, the result given by Netbeans is -66. Any ideas why?

asked Sep 15 '15 at 06:34

J.mp

1

Because Java doesn't have unsigned bytes (or unsigned anything, unless you count char). – Kayaman Sep 15 '15 at 06:35
You are doing the same thing as `(byte) 190` which is `-66` The mask isn't doing anything. – Peter Lawrey Sep 15 '15 at 06:37
1

By comparison you can do `byte b = (byte) i;` and `int j = b & 0xFF; // == 190` – Peter Lawrey Sep 15 '15 at 06:41

binary value comes wrong after & with 0x000000FF

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