Sorting hard a dictionary of lists

Asked Sep 16 '15 at 08:53

Active Sep 16 '15 at 09:17

Viewed 41 times

I have a data structure:

[{u'inch': [{3.5: u'3 1/2'}, {u'0.340': u'0.340'}, {u'0.560': u'0.560'}]}, {u'mm': [{40.0: Decimal('40.0')}, {70.0: Decimal('70.0')} {50.0: Decimal('50.0')}}]

I need to sort it {**3.5**: u'3 1/2'}, first value of dict. I need to get result:

[{u'inch': [{u'0.340': u'0.340'}, {u'0.560': u'0.560'}, {3.5: u'3 1/2'}]}, {u'mm': [{40.0: Decimal('40.0')}, {50.0: Decimal('50.0'), {70.0: Decimal('70.0')}}]

This code doesn't work:

[{k: sorted(v)} for k, v in attr_dict.items()]

edited Sep 16 '15 at 09:17

Joe Smart

asked Sep 16 '15 at 08:53

Nom Nom Lemon

1

in the value of `inch` key, in the first dict the key is float , but others are string?? And when you say `dont work` , what error/unexpected reuslt are you getting? – Anand S Kumar Sep 16 '15 at 08:55
realy, i set keys to float and its all works now. – Nom Nom Lemon Sep 16 '15 at 09:03

Sorting hard a dictionary of lists

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