PHP strtotime outputs 1970

Question

I have a string in an array which is like so

19/08/2015 12:08

I access this string using

$row["CREATE_DATE"]

If I do the following

var_dump($row["CREATE_DATE"] . "<br>");
var_dump(date("Ymd", strtotime($row["CREATE_DATE"])));

I get the output

string(20) "19/08/2015 12:08"
string(8) "19700101"

Why does the strtotime do my date as 1970?

Thanks

possible duplicate of [PHP date conversion to strtotime](http://stackoverflow.com/questions/32499055/php-date-conversion-to-strtotime) — Narendrasingh Sisodia, Sep 16 '15 at 11:22

score 3 · Accepted Answer · edited Sep 16 '15 at 12:00

3

You are doing it in wrong way.Use this :

var_dump(date("Ymd", strtotime(str_replace("/","-",$row["CREATE_DATE"]))));

See this link for all the supported date formats

edited Sep 16 '15 at 12:00

sanderbee

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answered Sep 16 '15 at 11:23

Happy Coding

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score 0 · Answer 2 · answered Sep 16 '15 at 11:31

<?
$row["CREATE_DATE"]="19/08/2015 12:08";
echo $d=date("Y-m-d", strtotime($row["CREATE_DATE"])); => 1970-01-01

But, When changing the format $row["CREATE_DATE"]="19-08-2015 12:08";
echo $d=date("Y-m-d", strtotime($row["CREATE_DATE"])); => 2015-08-19

So, What @RaveenaNigam Said, We Have To Use This Way.
var_dump(date("Ymd", strtotime(str_replace("/","-",$row["CREATE_DATE"]))));
=> 2015-08-19
?>

PHP strtotime outputs 1970

2 Answers2