Pass derived as base

Asked Sep 20 '15 at 06:56

Active Sep 20 '15 at 06:56

Viewed 37 times

I have the following code:

class Fruit {};
class Apple : public Fruit {};
class Banana : public Fruit {};

Apple** apples;
Banana** bananas;

void reportAboutFruit(Fruit** fruits);

When I try reportAboutFruit(apples); I get a compiler error, error: invalid conversion from 'Apple**' to 'Fruit**'.

I understand from this question why it would be dangerous to allow reportAboutFruit() to change the data, but as the function name implies I only want to read it, and I only need the stuff contained in the base Fruit class.

I am by no means a C++ expert, can someone explain how I can make this work?

edited May 23 '17 at 11:58

Community

asked Sep 20 '15 at 06:56

John

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`type**` is usually a red-flag design-wise in C++ – RamblingMad Sep 20 '15 at 07:01
why don't you use 'reportAboutFruit(Fruit* fruits)'? – D-rk Sep 20 '15 at 07:05
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Look here: http://stackoverflow.com/questions/2532422/conversion-of-pointer-to-pointer-between-derived-and-base-classes – Anorflame Sep 20 '15 at 07:10

Pass derived** as base**

0 Answers0

Pass derived as base